PersistenceException aufgetreten: org.hibernate.exception.ConstraintViolationException: konnte nicht einfügen: [Models.UJava

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Anonymous
 PersistenceException aufgetreten: org.hibernate.exception.ConstraintViolationException: konnte nicht einfügen: [Models.U

Post by Anonymous »

Ich habe diese Ausnahme !!
Hier ist meine Modellklasse < /p>

Code: Select all

@Entity
public class User extends Model {

@OneToMany(mappedBy="email", cascade=CascadeType.ALL)
public List photo;

@Email
@Required
@Unique
public String email;

@Required
public String passwordHash;

@Required
public String education;

@Required
public String fname;

@Required
public String lname;

@Required
public Date dob;

@Required
public String gender;

@Required
public String country;

@Required
public Long phone;

@Required
public String status;

@Required
public String jobtitle;

@Required
public String company;

@Required
public String industry;

@Required
public Date addDate;

public String needConfirmation;

public User(String email, String password, String fname,
String lname, Date dob, String gender, String country,
Long phone, String status, String education, String jobtitle, String company, String industry) {
//all initialization here
}
}
< /code>

Können Sie mir bitte sagen, wo ich falsch gehe
Playframework × 2289 < /p>



this is my photo class, and please tell me how can I allow JPA to generate my database

/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package models;

import controllers.Users;
import javax.persistence.Entity;
import javax.persistence.ManyToOne;
import play.db.jpa.Model;

/**
*
* @author nPandey
*/
@Entity
public class Photo extends Model{

public String photoname;

@ManyToOne
public User email;

public String owner;

public Photo(){

}

public Photo(User email, String photo){
this.photoname=photo;
this.email=email;
this.owner=email.email;
}

}

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