Django – Kontext muss ein Diktat und keine ReturnList sein ⇐ Python

[Anonymous]

Ich arbeite an einem Django-Projekt und habe ein Post-Modell, das diese Ansicht hat:

Code: Select all

class PostListApiView(ListCreateAPIView):
queryset = Post.objects.all()
serializer_class = PostSerializer
filter_backends = [SearchFilter]
search_fields = ['user','title','content']

Ich verwende diese Ansicht, um neue Beiträge zu erstellen:

Code: Select all

@method_decorator(login_required, name='dispatch')
class PostCreateView(APIView):
queryset = Post.objects.all()
serializer_class = PostCreateSerializer
renderer_classes = [TemplateHTMLRenderer]
permission_classes = [IsAuthenticated]
template_name = 'post_form.html'

def get(self, request, format=None):
serializer=PostCreateSerializer()
return Response({'serializer':serializer})

def post(self, request):
serializer = PostCreateSerializer(data=request.data)
if not serializer.is_valid():
return Response({'serializer':serializer})
serializer.save()
return redirect('/')

Ich möchte beide Ansichten in einer Ansicht konsolidieren

Code: Select all

class PostListApiView(ListCreateAPIView):
queryset = Post.objects.all()
serializer_class = PostSerializer
filter_backends = [SearchFilter]
search_fields = ['user','title','content']
renderer_classes = [TemplateHTMLRenderer]
template_name = 'post_form.html'

aber wenn ich versuche, den TemplateHTMLRenderer zur ListCreateAPIView hinzuzufügen, erhalte ich diese Fehlermeldung:

Code: Select all

Traceback (most recent call last):
File "C:\...\lib\site-packages\django\core\handlers\exception.py", line 34, in inner
response = get_response(request)
File "C:\...\lib\site-packages\django\core\handlers\base.py", line 145, in _get_response
response = self.process_exception_by_middleware(e, request)
File "C:\...\lib\site-packages\django\core\handlers\base.py", line 143, in _get_response
response = response.render()
File "C:\...\lib\site-packages\django\template\response.py", line 105, in render
self.content = self.rendered_content
File "C:\...\lib\site-packages\rest_framework\response.py", line 70, in rendered_content
ret = renderer.render(self.data, accepted_media_type, context)
File "C:\...\lib\site-packages\rest_framework\renderers.py", line 167, in render
return template.render(context, request=request)
File "C:\...\lib\site-packages\django\template\backends\django.py", line 59, in render
context = make_context(context, request, autoescape=self.backend.engine.autoescape)
File "C:\...\lib\site-packages\django\template\context.py", line 270, in make_context
raise TypeError('context must be a dict rather than %s.' % context.__class__.__name__)

Exception Type: TypeError at /posts/
Exception Value: context must be a dict rather than ReturnList.

Kann ich TemplateHTMLRenderer verwenden, um einen Abfragesatz und ein Formular in einer Vorlage zu rendern? Wenn nicht, wie kann ich das erreichen?
Vielen Dank