Fehler beim Erstellen von Bean mit dem in com.example.jpa.repository definierten Namen 'usserpo' ⇐ Java

[Anonymous]

Dies ist der Fehler Ich bekomme zum Zeitpunkt der Zusammenstellung. Ich bin neu im Frühling und kann den Fehler nicht verstehen. Plz hilft mir, es herauszufinden. < /P>

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org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepo' defined in com.example.jpa.repository.UserRepo defined in @EnableJpaRepositories declared on JpaRepositoriesRegistrar.EnableJpaRepositoriesConfiguration: Invocation of init method failed; nested exception is org.springframework.data.repository.query.QueryCreationException: Could not create query for public abstract java.util.List com.example.jpa.repository.UserRepo.findNameLike(java.lang.String)! Reason: Failed to create query for method public abstract java.util.List com.example.jpa.repository.UserRepo.findNameLike(java.lang.String)! No property findName found for type User!; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.List com.example.jpa.repository.UserRepo.findNameLike(java.lang.String)! No property findName found for type User!

Dies ist meine Repository -Klasse
Nach dem Fehler in der @Query bekomme ich jedoch, wie man repariert wird, und wo ist mein Fehler.

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package com.example.jpa.repository;

import java.util.List;

import javax.persistence.criteria.CriteriaBuilder.In;

import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Modifying;
import org.springframework.data.jpa.repository.Query;
import org.springframework.data.repository.CrudRepository;
import org.springframework.stereotype.Repository;

import com.example.jpa.entity.User;

@Repository
public interface UserRepo extends JpaRepository {
public List findByAgeGreaterThanEqual(int age) ;

public List findByAgeIn(int age);

public List findByNameOrderByName(String name);
@Modifying
@Query (value="select * from user1",nativeQuery=true)
public List getAllUser();
}

Dies ist meine Entitätsklasse

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package com.example.jpa.entity;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
//@Table(name = "user")
public class User {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;
private String name;
private String city;
private String status;

public User() {
super();

}
public User(int id, String name, String city, String status) {
super();
this.id = id;
this.name = name;
this.city = city;
this.status = status;
}

public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getStatus() {
return status;
}
public void setStatus(String status) {
this.status = status;
}
}

Dies ist meine Hauptanwendung Hauptklasse

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package com.example.jpa;

import java.util.List;
import java.util.Optional;

import org.apache.catalina.core.ApplicationContext;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.ConfigurableApplicationContext;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;

import com.example.jpa.entity.User;
import com.example.jpa.repository.UserRepo;

@SpringBootApplication
public class SpringApplicaton1Application {

public static void main(String[] args) {
ConfigurableApplicationContext context = SpringApplication.run(SpringApplicaton1Application.class, args);
UserRepo repo = context.getBean(UserRepo.class);

User user = new User();
user.setId(1);
user.setCity("Delhi");
user.setName("Ramesh");
user.setStatus("Java Developer");

List  users= repo.getAllUser();

users.forEach(n->{
System.out.println(n);

});

}

}

Dies ist meine Anwendung.property -Datei

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spring.datasource.name=test
spring.datasource.url=jdbc:mysql://${MYSQL_HOST:localhost}:3306/practice
spring.datasource.username=root
spring.datasource.password=root
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.MySQL55Dialect

spring.jpa.hibernate.use-new-id-generator-mappings= false

spring.jpa.hibernate.ddl-auto=update