Wie kann ich ein Array von einem nicht-nativen Funktionsaufruf zurückgeben? [Duplikat] ⇐ Php

[Guest]

Ich erhalte eine Fehlermeldung in dieser Zeile:

Code: Select all

$ret = array_merge($ret, preg_ls($path . "/" . $e, $rec, $pat));

Fehler ist:

array_merge() Argument #2 ist kein Array

Ich weiß nicht, wie ich das lösen soll.

Code: Select all

function preg_ls($path = ".", $rec = false, $pat = "/.*/") {
// it's going to be used repeatedly, ensure we compile it for speed.
$pat = preg_replace("|(/.*/[^S]*)|s", "\\1S", $pat);
//echo($pat);
//Remove trailing slashes from path
while (substr($path, -1, 1) == "/")
$path = substr($path, 0, -1);
//also, make sure that $path is a directory and repair any screwups
if (!is_dir($path)) $path = dirname($path);
//assert either truth or falsehoold of $rec, allow no scalars to mean truth
if ($rec !== true)
$rec = false;
//get a directory handle
$d = dir($path);
//initialise the output array
$ret = Array();
//loop, reading until there's no more to read
while (false !== ($e = $d->read())) {
//Ignore parent- and self-links
if (($e == ".") || ($e == "..")) continue;
//If we're working recursively and it's a directory, grab and merge
if ($rec && is_dir($path . "/" . $e)) {
$ret = array_merge($ret, preg_ls($path . "/" . $e, $rec, $pat));
continue;
}
//If it don't match, exclude it
if (!preg_match($pat, $e))
continue;
//In all other cases, add it to the output array
//echo ($path . "/" . $e . "
");
$ret[] = $path . "/" . $e;
}
//finally, return the array
echo json_encode($ret);
}