Anonymous
Ich arbeite an einem Projekt und meine Ergebnisabfrage liefert mehrere Datensätze, aber ich möchte jeden Datensatz nur g
Post
by Anonymous » 29 Dec 2025, 05:04
Code: Select all
$this->db
->select(array('courses.Course_Name','teacher.First_Name','teacher.Last_Name','teacher.Reg_Id','teacher_assignment.Assignment_Id','Assignment_Url','assignment.Solution_Url','assignment.Status','courses.Course_Id'));
$this->db
->from(array('student_registration'));
$this->db
->join('courses','student_registration.Course_Id=courses.Course_Id','inner');
$this->db
->Join('teacher_assignment','teacher_assignment.Course_Id=courses.Course_Id','inner');
$this->db
->Join('assignment','assignment.OEN_Number = student_registration.OEN_Number','teacher_assignment.Reg_Id = assignment.Reg_Id','inner');
$this->db
->Join('teacher','teacher.Reg_Id = assignment.Reg_Id','inner');
$this->db
->where(array('student_registration.OEN_Number'=> $uid));
$query = $this->db->get();
1766981043
Anonymous
[code]$this->db ->select(array('courses.Course_Name','teacher.First_Name','teacher.Last_Name','teacher.Reg_Id','teacher_assignment.Assignment_Id','Assignment_Url','assignment.Solution_Url','assignment.Status','courses.Course_Id')); $this->db ->from(array('student_registration')); $this->db ->join('courses','student_registration.Course_Id=courses.Course_Id','inner'); $this->db ->Join('teacher_assignment','teacher_assignment.Course_Id=courses.Course_Id','inner'); $this->db ->Join('assignment','assignment.OEN_Number = student_registration.OEN_Number','teacher_assignment.Reg_Id = assignment.Reg_Id','inner'); $this->db ->Join('teacher','teacher.Reg_Id = assignment.Reg_Id','inner'); $this->db ->where(array('student_registration.OEN_Number'=> $uid)); $query = $this->db->get(); [/code]