Schaffung von Magic Square 3x3 ⇐ Python

[Anonymous]

Ich suche nach einer Möglichkeit, die Kreation Magic Square 3x3 < /p>
zu vereinfachen

Code: Select all

def getCost(arr, magic):
return sum(abs(arr[i][j] - magic[i][j]) for i in range(3) for j in range(3))

def formingMagicSquare(s):
magic_squares = [
[[8, 1, 6], [3, 5, 7], [4, 9, 2]],
[[6, 7, 2], [1, 5, 9], [8, 3, 4]],
[[2, 9, 4], [7, 5, 3], [6, 1, 8]],
[[4, 3, 8], [9, 5, 1], [2, 7, 6]],
[[6, 1, 8], [7, 5, 3], [2, 9, 4]],
[[2, 7, 6], [9, 5, 1], [4, 3, 8]],
[[4, 9, 2], [3, 5, 7], [8, 1, 6]],
[[8, 3, 4], [1, 5, 9], [6, 7, 2]]
]

minCost = float('inf')
for square in magic_squares:
cost = getCost(square, s)
minCost = min(minCost, cost)
return minCost